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FTCE Physics (032) Practice Tests & Test Prep by Exam Edge - Free Test


Our free FTCE Physics 6-12 (032) Practice Test was created by experienced educators who designed them to align with the official Florida Teacher Certification Examinations content guidelines. They were built to accurately mirror the real exam's structure, coverage of topics, difficulty, and types of questions.

Upon completing your free practice test, it will be instantly reviewed to give you an idea of your score and potential performance on the actual test. Carefully study your feedback to each question to assess whether your responses were correct or incorrect. This is an effective way to highlight your strengths and weaknesses across different content areas, guiding you on where to concentrate your study efforts for improvement on future tests. Our detailed explanations will provide the information you need to enhance your understanding of the exam content and help you build your knowledge base leading you to better test results.

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FTCE Physics 6-12 - Free Test Sample Questions

A satellite of mass Ms is in motion with velocity v. If R stands for radius, which   equation is correct for the calculation of the centripetal force?
 

Correct Answer:
  fnet = (ms x v2)/r


to understand why the correct equation for calculating the centripetal force acting on a satellite is fnet = (ms x v^2)/r, it's important to delve into the concept of centripetal force and its role in circular motion.

centripetal force is the force that keeps an object moving in a circular path and is directed towards the center around which the object is moving. this force is crucial for maintaining the circular motion of the satellite orbiting around a planet or another celestial body. the formula for centripetal force is derived from the basic principles of motion.

the centripetal force (f_c) necessary to keep an object of mass m moving at a velocity v along a circular path of radius r is given by the equation: \[ f_c = \frac{m \times v^2}{r} \] here, m represents the mass of the object (in this case, the satellite), v is the velocity of the satellite, and r is the radius of the circular orbit.

in the context of the question, ms stands for the mass of the satellite. thus, replacing m with ms in the centripetal force formula, we get: \[ f_{\text{net}} = \frac{ms \times v^2}{r} \] this equation shows that the net centripetal force (fnet) acting on the satellite is proportional to the square of its velocity and inversely proportional to the radius of its orbit. the mass of the satellite also directly influences the magnitude of this force.

the formula ensures that the satellite remains in orbit by counteracting the inertia of the satellite that would otherwise propel it in a straight line, according to newton's first law of motion. without this centripetal force, the satellite would not be able to maintain its circular orbit and would instead move off into space along a tangential line.

understanding this equation and its derivation from fundamental physics principles is essential for designing stable satellite orbits and for predicting the behavior of satellites and other celestial bodies in circular motion. this is why fnet = (ms x v^2)/r is the correct and only viable equation among the given choices for calculating the centripetal force acting on a satellite.