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ILTS Science: Physics (116) Practice Tests & Test Prep by Exam Edge

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ILTS Science Physics Sample Test

1 of 5

Which parameter is required to calculate the acceleration of a body?

Correct Answer:

the rate of change in velocity of the body
to calculate the acceleration of a body, the parameter required is "the rate of change in velocity of the body."

acceleration is defined as the rate at which the velocity of an object changes over time. it is a vector quantity, meaning it has both magnitude and direction. the formula used to calculate acceleration (a) is given by the change in velocity (δv) divided by the time interval (δt) during which this change occurs. mathematically, it is expressed as: \[ a = \frac{\delta v}{\delta t} \]

velocity itself is a vector quantity that specifies the speed of an object and the direction of its motion. therefore, acceleration occurs not only when the speed of an object changes but also when its direction of motion changes. this highlights why acceleration cannot be accurately determined by merely knowing the speed or the velocity at a specific instant. instead, knowing how velocity changes over time is crucial.

the units of acceleration are meters per second squared (m/s²). this unit arises because velocity is measured in meters per second (m/s) and time in seconds (s). therefore, when calculating the rate of change of velocity (m/s per second), the resulting unit is m/s².

it's important to differentiate between speed and velocity in this context. speed is a scalar quantity that only measures how fast an object is moving, irrespective of its direction. since acceleration involves a change in velocity (not just speed), understanding the vector nature of velocity and its changes over time is essential for calculating acceleration.

in summary, to find the acceleration of a body, it is imperative to know the rate at which its velocity changes. this includes changes in the speed and direction of the body. without this information, it is not possible to determine the acceleration accurately.