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MCA Middle Science (013) Practice Tests & Test Prep by Exam Edge - Free Test


Our free MCA Middle School Education Science (013) Practice Test was created by experienced educators who designed them to align with the official Missouri Content Assessments content guidelines. They were built to accurately mirror the real exam's structure, coverage of topics, difficulty, and types of questions.

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MCA Middle School Education Science - Free Test Sample Questions

A spinning top has a moment of inertia equal to 50 kgm2 and an angular speed of 10 rad/s. What is the rotational kinetic energy of the top?





Correct Answer:
2500 j


to determine the rotational kinetic energy of a spinning top, we use the formula for rotational kinetic energy, which is given by \( k_{\text{rotational}} = \frac{1}{2} i \omega^2 \). in this equation, \( i \) represents the moment of inertia, and \( \omega \) represents the angular velocity of the top.

in the given problem, the moment of inertia \( i \) is specified as 50 kgm\(^2\), and the angular velocity \( \omega \) is provided as 10 rad/s. plugging these values into the formula, we calculate the rotational kinetic energy as follows: \[ k_{\text{rotational}} = \frac{1}{2} \times 50 \, \text{kgm}^2 \times (10 \, \text{rad/s})^2 \] \[ k_{\text{rotational}} = \frac{1}{2} \times 50 \times 100 \] \[ k_{\text{rotational}} = 2500 \, \text{joules} \]

therefore, the rotational kinetic energy of the spinning top is 2500 joules. this energy represents the amount of work that has been done to get the top spinning at the specified angular velocity, and it also indicates the amount of energy that would be needed to bring the top to a stop from its spinning state.