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MTTC Industrial Technology (087) Practice Tests & Test Prep by Exam Edge - Free Test


Our free MTTC Industrial Technology Education (129) Practice Test was created by experienced educators who designed them to align with the official Michigan Test for Teacher Certs content guidelines. They were built to accurately mirror the real exam's structure, coverage of topics, difficulty, and types of questions.

Upon completing your free practice test, it will be instantly reviewed to give you an idea of your score and potential performance on the actual test. Carefully study your feedback to each question to assess whether your responses were correct or incorrect. This is an effective way to highlight your strengths and weaknesses across different content areas, guiding you on where to concentrate your study efforts for improvement on future tests. Our detailed explanations will provide the information you need to enhance your understanding of the exam content and help you build your knowledge base leading you to better test results.

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MTTC Industrial Technology Education - Free Test Sample Questions

If an LED (light-emitting diode) requires 1.5 volts at 30 milliamps of drive current, its power rating is:

Correct Answer:
45 milliwatts
to determine the power rating of a light-emitting diode (led) when given its required voltage and current, we use the basic power formula from electrical engineering, which states that power (p) is the product of voltage (e) and current (i). the formula is expressed as: \[ p = e \times i \]

in this scenario, the led requires a voltage (e) of 1.5 volts and a current (i) of 30 milliamps to operate correctly. however, it's important to remember that the units should be consistent when applying the formula. since power is typically calculated in watts, and 1 amp equals 1000 milliamps, we need to convert the current from milliamps to amps before using the formula. here's how the conversion and calculation are done: 1. convert current from milliamps to amps: \[ 30 \text{ milliamps} = 30 \times 10^{-3} \text{ amps} = 0.03 \text{ amps} \] 2. apply the power formula: \[ p = e \times i = 1.5 \text{ volts} \times 0.03 \text{ amps} = 0.045 \text{ watts} \] 3. convert power from watts to milliwatts (since 1 watt = 1000 milliwatts): \[ 0.045 \text{ watts} = 45 \text{ milliwatts} \]

therefore, the power rating of the led is 45 milliwatts. this calculation ensures that the led's power requirements are met to function efficiently without overloading or damaging the component. understanding and applying these calculations is crucial in electronic circuit design to ensure that all components operate within their specified power limits.