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NES Physics (308) Practice Tests & Test Prep by Exam Edge

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NES 308 Practice Test Features

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NES Physics Sample Test

1 of 5

For motion in a circle of radius R, the angular rate of rotation is ω=2π/T. What is the speed of the object travelling the circle?

Correct Answer:

ωr

for motion in a circle of radius r, the circumference of the circle is 2πr. if the period for one complete rotation around the circle is t, the angular rate of rotation, denoted as ω, is given by ω = 2π/t. this equation derives from the fact that the angular displacement for one complete rotation is 2π radians, and the time it takes to complete this rotation is t.

to find the linear or tangential speed (v) of the object traveling along the circumference of the circle, we use the relationship between linear speed, angular speed, and radius. the linear speed v is the product of the angular speed ω and the radius r of the circle. substituting the expression for ω, we have v = ωr = (2π/t)r. this simplifies to v = 2πr/t, which represents the distance traveled per unit time, or speed.

therefore, the speed of the object traveling in the circle, with radius r and period t, is given by 2πr/t or equivalently ωr. both expressions represent the same physical quantity — the speed at which the object moves along the circle's circumference. hence, the correct answer to the question is ωr.